- A$Se$
- ✓$As$
- C$Ga$
- D$Ge$
$Br ^{+2}$ is : $[ Ar ]\, 3 d ^{10} \,4 s ^2\, 4 p ^3$
The electronic configuration of $Br ^{+2}$ is hence identical with the element Arsenic.
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[Given : $pKa$ (acetic acid) $=4.74$ ]
$N_{2}=3.0 \times 10^{-3} M$
$O_{2}=4.2 \times 10^{-3} M$
and $N O=2.8 \times 10^{-3} M$
in a sealed vessel at $800 \,K$ and $1$ $atm$ pressure.........$atm$ will be $K_{p}$ for the given reaction?
$N_{2}(g)+O_{2}(g) \rightleftharpoons 2 N O(g)$
$\begin{array}{*{20}{c}} {{H_3}C - C{H_2} - CH - Et} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \end{array}$ about $C_2-C_3$ is (figure) 