Question
If $\displaystyle \begin{vmatrix}\text{x} &\text{amp; } 1 \\ \text{y} &\text{amp; } 2 \end{vmatrix}-\displaystyle \begin{vmatrix}\text{y} &\text{amp; } 1 \\ 8&\text{amp; } 0\end{vmatrix}=\displaystyle \begin{vmatrix}2 &\text{amp; } 0 \\ \text{-x}&\text{amp; } 2\end{vmatrix}$ then the values of x and y respectively are:
  1. 5 and 1 
  2. 5 and 3
  3. 5 and 2
  4. 3 and 4

Answer

  1. 5 and 3

Solution:

x - y = 2

y - 8 = -x

Solving we get x = 5 and y = 3

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