Rajasthan BoardEnglish MediumSTD 9MATHSNumber systems1 Mark
Question
If $\frac{2+\sqrt{3}}{2-\sqrt{3}}=\text{a}+\text{b}\sqrt{3},$ then,
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Answer
a = 7 and b = 4 Solution: $\frac{2+\sqrt{3}}{2-\sqrt{3}}$ Multiplying numerator and denominator by $2\div\sqrt{3}$ So, $\frac{(2+\sqrt{3})^2}{(2-\sqrt{3})(2+\sqrt{3})}$ $=\frac{4+3+4\sqrt{3}}{4-3},$ $=7\div4\sqrt{3}$ Now equating $7\div4\sqrt{3}$ and $\text{a}\div\text{b}\sqrt{3}$ we get, a = 7 and b = 4
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