MCQ
If $i,\,j,\,k$ are the unit vectors and mutually perpendicular, then $[i\,k\,j]$ is equal to
  • A
    $0$
  • $-1$
  • C
    $1$
  • D
    None of these

Answer

Correct option: B.
$-1$
b
(b) $|i\,k\,j|\, = i\,.\,(k \times j) = i\,.\,( - i) = - 1.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Area bounded by the lines $y = x,\,\,x = - 1,\,\,x = 2$ and $x - $ axis is
Area of the region enclosed between the curves $x = y^2 -1$ and $x = |y|$ $\sqrt {1 - {y^2}} $ is
The corner points of the feasible region determined by the system of linear inequalities are $(0, 0), (4, 0), (2, 4)$ and $(0, 5).$ If the maximum value of $z = ax + by,$ where $a, b > 0$ occurs at both $(2, 4)$ and $(4, 0),$ then:
$$f(x)=\left| {\begin{array}{*{20}{c}} {{{\sin }^2}x}&{ - 2 + {{\cos }^2}x}&{\cos 2x} \\ {2 + {{\sin }^2}x}&{{{\cos }^2}x}&{\cos 2x} \\ {{{\sin }^2}x}&{{{\cos }^2}x}&{1 + \cos 2x} \end{array}} \right| ,x \in[0, \pi]$$

Then the maximum value of $f(x)$ is equal to $.....$

Match the statements/expressions given in Column $I$ with the values given in Column $II$.

Column $I$ Column $II$

$(A)$ Root$(s)$ of the equation

$2 \sin ^2 \theta+\sin ^2 2 \theta=2$

$(p)$ $\frac{\pi}{6}$

$(B)$ Points of discontinuity of the function

$f(x)=\left[\frac{6 x}{\pi}\right] \cos \left[\frac{3 x}{\pi}\right],$

where $[y]$ denotes the largest integer less than or equal to $y$

$(q)$ $\frac{\pi}{4}$

$(C)$ Volume of the parallelopiped with its edges represented by the vectors

$\hat{i}+\hat{j}, \quad \hat{i}+2 \hat{j} \text { and } \hat{i}+\hat{j}+\pi \hat{k}$

$(r)$ $\frac{\pi}{3}$

$(D)$ Angle between vectors $\vec{a}$ and $\vec{b}$ where $\vec{a}, \vec{b}$ and $\vec{c}$ are unit vectors satisfying

$\vec{a}+\vec{b}+\sqrt{3} \vec{c}=\overrightarrow{0}$

$(s)$ $\frac{\pi}{2}$
  $(t)$ $\pi$
If $A = \left[ {\begin{array}{*{20}{c}}i&0\\0&{i/2}\end{array}} \right]$ $(i = \sqrt { - 1} ),$then ${A^{ - 1}}$=
Let $\mathrm{A}=\left[\begin{array}{ccc}1 & \sin \theta & 1 \\ -\sin \theta & 1 & \sin \theta \\ -1 & -\sin \theta & 1\end{array}\right],$ where $0 \leq \theta \leq 2 \pi$. Then
The degree of the differential equation $\frac{\text{d}^3\text{y}}{\text{dx}^3}+3\frac{\text{d}^2\text{y}}{\text{dx}^2}=\text{x}^2\log\frac{\text{d}^3\text{y}}{\text{dx}^3}$ is:
If $f(x) = 3x + 10$, $g(x) = {x^2} - 1$, then ${(fog)^{ - 1}}$ is equal to
The area of region enclosed by the parabolas  ${y^2} = 4x$ and ${x^2} = 4y$ is