MCQ
If $\int_{}^{} {x\sin xdx = - x\cos x + A} $, then $A = $
- ✓$\sin x + $constant
- B$\cos x + $constant
- CConstant
- DNone of these
✓
Answer
Correct option: A.
$\sin x + $constant
a
(a) Since,$\int_{}^{} {x\sin x\,dx} = - x\cos x + A$
$ \Rightarrow - x\cos x + \sin x + {\rm{constant}} = - x\cos x + A$
Equating it, we get $A = \sin x + {\rm{constant}}{\rm{.}}$
(a) Since,$\int_{}^{} {x\sin x\,dx} = - x\cos x + A$
$ \Rightarrow - x\cos x + \sin x + {\rm{constant}} = - x\cos x + A$
Equating it, we get $A = \sin x + {\rm{constant}}{\rm{.}}$
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