MCQ
If $m$ and $\sigma ^2$ are the mean and variance of random variable $x$, whose distribution is given by
$\begin{array}{|l|l|l|l|l|l|} \hline X=x & 0 & 1 & 2 & 3 & 4 \\ \hline P(X=x) & \frac{1}{3} & \frac{1}{2} & 0 & \frac{1}{6} & 0 \\ \hline \end{array}$
, then
- A$m = {\sigma ^2} = 2$
- B$m = 1,{\sigma ^2} = 2$
- ✓$m = {\sigma ^2} = 1$
- D$m = 2,{\sigma ^2} = 1$