MCQ
If $pOH $ of a solution is $6.0$ , then its $pH$ will be
- A$6$
- B$10$
- ✓$8$
- D$14$
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Reason : In the complex, the coordination number of $Fe$ is $6$.

$CH \equiv CH\xrightarrow[{(excess)}]{{NaN{H_2}/liq.N{H_3}}}A\xrightarrow{{2C{H_3} - I}}B\xrightarrow[{quinolene}]{{{H_2}/Pd - BaS{O_4}}}C$
$C\xrightarrow[{quinolene}]{{{H_2}/Pd - BaS{O_4}}}\xrightarrow[{liq.\,N{H_3}}]{{NaN{H_2}}}D$