MCQ
If ${\sin ^{ - 1}}\frac{1}{2} = {\tan ^{ - 1}}x,$ then $ x =$
- A$\sqrt 3 $
- ✓$\frac{1}{{\sqrt 3 }}$
- C$\frac{1}{{\sqrt 2 }}$
- DNone of these
$ \Rightarrow \,\,{\tan ^{ - 1}}x = \frac{\pi }{6}$
$ \Rightarrow \,\,x = \tan {30^o} = \frac{1}{{\sqrt 3 }}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$STATEMENT -1$ : The function $F(x)$ satisfies $F(x+\pi)=F(x)$ for all real $x$. because
$STATEMENT -2$$: \sin ^2(x+\pi)=\sin ^2 x$ for all real $x$.