MCQ
If $\tan (x + y) = 33$ and $x = {\tan ^{ - 1}}3,$ then $y $ will be
  • A
    $0.3$
  • B
    ${\tan ^{ - 1}}(1.3)$
  • ${\tan ^{ - 1}}(0.3)$
  • D
    ${\tan ^{ - 1}}\left( {\frac{1}{{18}}} \right)$

Answer

Correct option: C.
${\tan ^{ - 1}}(0.3)$
c
(c) $x + y = {\tan ^{ - 1}}33\,\,\, $

$\Rightarrow y = {\tan ^{ - 1}}33 - {\tan ^{ - 1}}3$

$ = {\tan ^{ - 1}}\frac{{33 - 3}}{{1 + 99}} = {\tan ^{ - 1}}\frac{{30}}{{100}}$

==> $y = {\tan ^{ - 1}}(0.3)$.

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