MCQ
If the constraints in linear programming problem are changed.
  • A
    The problem is to be re - evaluated
  • B
    Solution is not defined
  • C
    The objective function has to be modified
  • D
    The change in constraints is ignored

Answer

  1. The problem is to be re - evaluated

Solution:

The above question asks for the impact of change in constraints on the Linear programming problem.

In this scenario, when there is a change in constraint, the solution will change definitely.

Whether the solution exists or not, we can only find once the problem is re - evaluated.

In an LPP, the objective function is related to the main objective of any problem, either we have to maximize or minimize the function based on the situation whereas the constraints is related to physical restrictions in achieving the defined objective function.

In real life problems, there might be situations when the constraints change, but objective function does not changes to accommodate the change in constraints.

Thus, if constraints in linear programming problem is changed, the problem has to be re - evaluated for the same objective function and after solving we can find whether the solution exists or not.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Let $S=\{1,2,3, \ldots, 10\}$. Suppose $M$ is the set of all the subsets of $S$, then the relation $R=\{(A, B): A \cap B \neq \phi ; A, B \in M\}$ is :
The acute angle between the line joining the points $(2,1,-3), (-3,1,7)$ and a line parallel to $\frac{{x - 1}}{3} = $ $\frac{y}{4} = \frac{{z + 3}}{5}$ through the point $(-1, 0, 4)$ is
The solution of the differential equation $\frac{{dy}}{{dx}} + 2y\cot x = 3{x^2}{\rm{cose}}{{\rm{c}}^2}x$ is
If $\left[ {\begin{array}{*{20}{c}}1&2&3\\3&1&2\\2&3&1\end{array}} \right]\,\left[ \begin{array}{l}x\\y\\z\end{array} \right] = \left[ {\begin{array}{*{20}{c}}4&{ - 2}\\0&{ - 6}\\{ - 1}&2\end{array}} \right]\,\left[ \begin{array}{l}2\\1\end{array} \right]$, then $(x,y,z)$=
If $y=a e^x+b e^{-x}+c$, where $a, b, c$ are parameters, then $y^{\prime}$ is equal to
India play two matches each with West indies and Australia. In any match the probability of india getting 0,1 and 2 points are 0.45, 0.05 and 0.50 respectively. Assuming that the outcomes are indepecdent, the probability of india getting at least 7 points is.
Let $A\,=\,\{\,x\,\in \,R\,:\,x$ is not a positive int eger $\}$ Define a function $f\,:\,A\,\to \,R$ as $f\,(x)\, = \frac{{2x}}{{x - 1}}$ then $f$ is
Derivative of $e^{2 x}$ with respect to $e^x$, is
If $ 5$  is one root of the equation $\left| {\,\begin{array}{*{20}{c}}x&3&7\\2&x&{ - 2}\\7&8&x\end{array}\,} \right| = 0$, then other two roots of the equation are
Let $S=\{1,2,3,4,5,6\}$. Then the number of oneone functions $f: S \rightarrow P(S)$, where $P(S)$ denote the power set of $S$, such that $f(n) \subset f(m)$ where $n < m$ is $..................$