MCQ
If two angles in a triangle are $40^\circ $ and $60^\circ $, then the third angle is:
- A$90^\circ$
- ✓$80^\circ$
- C$70^\circ$
- D$60^\circ$
Let the third angle be $x$ Sum of angles $= 180^\circ 40^\circ + 60^\circ + x = 180^\circ 100^\circ + x = 180^\circ $
$\Rightarrow x = 80^\circ $
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| Ratio | Decimal | Per cent |
| $\frac{3}{10}=\frac{30}{100}$ | $0.30$ | $30\%$ |
| $\frac{1}{2}=\frac{50}{100}$ | $0.50$ | $50\%$ |
| $\frac{3}{4}=\frac{75}{100}$ | $0.75$ | $75\%$ |