Question
If X follows a binomial distribution with parameter $\text{n}=100$ and $\text{p}=\frac{1}{3},$ then P(X = r) is maximum when r = 
  1. 32
  2. 34
  3. 33
  4. 31

Answer

  1. 33

Solution:

$\text{n}=100,\text{p}=\frac{1}{3}\Rightarrow\text{q}=\frac{2}{3}$

$\text{np}=\frac{100}{3}=33+\frac{1}{3}$

⇒ Probability is maximum at 33.

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