Question
If X follows a binomial distribution with parameter $\text{n}=100$ and $\text{p}=\frac{1}{3},$ then P(X = r) is maximum when r =
- 32
- 34
- 33
- 31
Solution:
$\text{n}=100,\text{p}=\frac{1}{3}\Rightarrow\text{q}=\frac{2}{3}$
$\text{np}=\frac{100}{3}=33+\frac{1}{3}$
⇒ Probability is maximum at 33.
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