MCQ
If $y^2(2-x)=x^3$, then $\left(\frac{d y}{d x}\right)_{(1,1)}$ is equal to
  • A
    2
  • B
    -2
  • C
    3
  • D
    $-3 / 2$

Answer

$\begin{array}{l}\text {Given, } y^2(2-x)=x^3 \\ \Rightarrow y^2=\frac{x^3}{2-x} \Rightarrow 2 y \cdot \frac{d y}{d x}=\frac{(2-x) \times 3 x^2-x^3(-1)}{(2-x)^2} \\ \Rightarrow \frac{d y}{d x}=\frac{6 x^2-2 x^3}{2 y(2-x)^2} \Rightarrow\left(\frac{d y}{d x}\right)_{(1,1)}=\frac{6-2}{2 \times 1}=2\end{array}$

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