- AF = 0
- BF = 180N
- CF = -180N
- DF = 3600N
Explanation:
Magnetic force on a proton is $\text{Fm}=\text{qv}\text{B}\sin(\theta).$
A proton moving parallel or antiparallel to a magnetic field does not experience any force.
Hence, the proton does not get deflected while moving through a magnetic field region.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Three infinitely long charge sheets are placed as shown in figure. The electric field at point P is
|
(a) |
(b) |
(c) |
(d) |
What will be the ratio of de-Broglie wavelengths of proton and α - particle of same energy
|
(a) 2 : 1 |
(b) 1 : 2 |
(c) 4 : 1 |
(d) 1 : 4 |
There are two equipotential surface as shown in figure. The distance between them is r. The charge of –q coulomb is taken from the surface A to B, the resultant work done will be
|
(a) |
(b) |
(c) |
(d) |