In a double slit interference experiment, the separation between … - Vidyadip

Question

In a double slit interference experiment, the separation between the slits is $1.0\ mm,$ the wavelength of light used is $5.0 \times 10^{-7}m$ and the distance of the screen from the slits is $1.0m$.

Find the distance of the centre of the first minimum from the centre of the central maximum.
How many bright fringes are formed in one centimeter width on the screen?

✓

Answer

Given that$, d = 1\ mm = 10^{-3}m, D = 1m.$
So, fringe with $=\frac{\text{D}\lambda}{\text{d}}=0.5\ \text{mm}.$

So, distance of centre of first minimum from centre of central maximum $=\frac{0.5}{2}\ \text{mm}=0.25\ \text{mm}$
No. of fringes $\frac{10}{0.5}=20.$

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