- AArea of the plate is decreased.
- BDistance between the plates is increases.
- CArea of the plate is increased.
- DDielectric constant decreases.
Explanation:
Hint:- Check the dependence of capacitance on certain quantities.
In a parallel plate capacitor, the capacitance is $\text{C}=\frac{\text{k}\in_0\text{A}}{\text{d}};$
Where, k is the dielectric constant, $\in_0$ is the permittivity constant, A is the area of the conduction and d is the distance between plates.
From here we can see C is directly proportional to k, $\in_0$,A and inversely proportional to d.
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