In a potentiometer arrangement, a cell of $emf$ $1.25\; V$ gives a balance point at $35.0\; cm$ length of the wire. If the cell is replaced by another cell and the balance point shifts to $63.0\; cm ,$ what is the $emf$ of the second cell in $V$?
Medium
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$Emf$ of the cell, $E_{1}=1.25\, V$
Balance point of the potentiometer, $l_{1}=35 \,cm$
The cell is replaced by another cell of $emf$ $E_{2}$
New balance point of the potentiometer, $l_{2}=63 \,cm$
The balance condition is given by the relation,
$\frac{E_{1}}{E_{2}}=\frac{l_{1}}{l_{2}}$
$E_{2}=E_{1} \times \frac{l_{2}}{l_{1}}$
$=1.25 \times \frac{63}{35}=2.25 \,V$
Therefore, $emf$ of the second cell is $2.25\, V$
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