In a potentiometer circuit there is a cell of $e.m.f.$ $2\, volt$, a resistance of $5\, ohm$ and a wire of uniform thickness of length $1000\, cm$ and resistance $15\, ohm$. The potential gradient in the wire is
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Potential gradient $x = \frac{V}{L} = \frac{{iR}}{L}$
$ \Rightarrow $ $x = \frac{2}{{(15 + 5)}} \times \frac{{15}}{{10}} = \frac{3}{{2000}}\,volt/cm$
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