In a Wheatstone’s bridge all the four arms have equal resistance R. If the resistance of the galvanometer arm is also R, the equivalent resistance

Q: In a Wheatstone’s bridge all the four arms have equal resistance $R$. If the resistance of the galvanometer arm is also $R$, the equivalent resistance of the combination as seen by the battery is

b (b) As bridge is in balanced condition, no current will flow through $BD.$ $R_{1}=R_{A B}+R_{B C}$ $=R+R=2 R$ $R_{2}=R_{A D}+R_{C D}=R+R=2 R$ Also, $R_{1}$ and $R_{2}$ are in parallel combination Hence, equivalent resistance between $A$ and $C$ will be $R_{e q}=\frac{R_{1} R_{2}}{R_{1}+R_{2}}=\frac{4 R^{2}}{4 R}=R$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

In a Wheatstone’s bridge all the four arms have equal resistance $R$. If the resistance of the galvanometer arm is also $R$, the equivalent resistance of the combination as seen by the battery is

A$\frac{R}{2}$
B$R$
C$2 R$
D$\frac{R}{4}$

AIPMT 2003, Easy

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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