- Athe velocity of both the particles may be same after the collision
- Bkinetic energy is not conserved
- Clinear momentum of the system is conserved.
- ✓All of the above
Final velocities of both the body is same
But, when the collision is not perfectly inelastic the velocities differ.
Thus, the final velocity of the bodies may or may not be same.
Also, there is a loss of kinetic energy during an inelastic collision.
thus, kinetic energy is not conserved and velocity of separation will be less than
velocity of approach.
A collision, let it be elastic or inelastic has always its momentum conserved and
is given by,
$m_1 u_1+m_2 u_2=m_1 v_1+m_2 v_2$
Thus, linear momentum of the system is conserved
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$\text{F = Mg}$
$\text{F}=\mu\text{Mg}$
$\text{Mg}\leq\text{F}\leq\text{Mg}\sqrt{1+\mu^2}$
$\text{Mg}\geq\text{F}\geq\text{Mg}\sqrt{1-\mu^2}.$

Main scale reading : $58.5$ degree
Vernier scale reading : $09$ divisions
Given that $1$ division on main scale corresponds to $0 .5$ degree. Total divisions on the Vernier scale is $30$ and match with $29$ divisions of the main scale. The angle of the prism from the above data ....... $degree$