MCQ
In Cannizzaro reaction given below
$2PhCHO \xrightarrow{{:\mathop O\limits^ \ominus H}}PhC{H_2}OH + PhC\mathop {O_2^ \ominus }\limits^{.\,\,.\,\,} $
the slowest step is :
- ✓the transfer of hydride to the carbonyl group
- Bthe abstraction of proton from the carboxylic group
- Cthe deprotonation of $Ph CH_2OH$
- Dthe attack of ${:\mathop O\limits^ \ominus H}$ at the carboxyl group
