In order to determine the $e.m.f.$ of a storage battery it was connected in series with a standard cell in a certain circuit and a current $I_1$ was obtained. When the battery is connected to the same circuit opposite to the standard cell a current $I_2$ flow in the external circuit from the positive pole of the storage battery was obtained. What is the $e.m.f$. $\varepsilon_1$ of the storage battery? The $e.m.f$. of the standard cell is $\varepsilon_2$.
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$\varepsilon_{1}+\varepsilon_{2}=I_{1} R, \varepsilon_{1}-\varepsilon_{2}=I_{2} R$

Dividing $\varepsilon_{1}=\left(\frac{I_{1}+I_{2}}{I_{1}-I_{2}}\right) \varepsilon_{2}$

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