MCQ
In TeCl4, the central atom tellurium involves:
- Asp3 hybridisation
- Bsp3d hybridisation
- Cdsp2 hybridisation
- Dsp3d2 hybridisation
Explanation:
Number of hybrid orbitals =$\frac{1}{2}$ (no. of electrons in valence shell of atom + no. of monovalent atoms - charge no cation + charge on the anion.
Number of hybride orbitals =$\frac{1}{2}$(6+4+0+0) = 5
Hence, TeCl4 shows sp3d hybridisation.
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