MCQ
In the electric network shown, when no current flows through the $4 \Omega$ resistor in the arm EB, the potential difference between the points $A$ and $D$ will be $.............\,V$


- A$6$
- B$3$
- ✓$5$
- D$4$

As no current flows through arm $E B$ then $V _{ D }=0 V ; \quad V _{ E _{ D }}=0 V ; \quad V _{ B }=-4 V ; \quad V _{ A }=5 V$ So, potential difference between the points $A$ and $D$
$V_A-V_D=5\,V$
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$\mathrm{f}_1=10 \mathrm{~cm} \quad \mathrm{f}_2=10 \quad \mathrm{f}_3=30 \mathrm{~cm}$