MCQ
In the given circuit, with steady current, the potential drop across the capacitor must be
- A$V$
- B$V/2$
- ✓$V/3$
- D$2V/3$
✓
Answer
Correct option: C.
$V/3$
c
in sleady state
in sleady state
$I=\frac{2 V-V}{2 R+R}=\frac{V}{3 R}$
Potential differnce across $"\mathrm{R}"$ $=\frac{\mathrm{V}}{3 \mathrm{R}} \times \mathrm{R}=\frac{\mathrm{V}}{3}$
$\therefore \mathrm{V}_{\mathrm{AB}}=\mathrm{V}+\frac{\mathrm{V}}{3}$
and
So potential difference across $\mathrm{C}=\frac{\mathrm{V}}{3}$
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