Answer

  1. 60º
    Solution:
    In triangle ABC, $\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ$
    $\Rightarrow\angle\text{C}=60^\circ$
    $\angle\text{ACB}=\angle\text{ADB}=60^\circ$ (Angle made by the same chord are equal)

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