MCQ
In the lowest energy level of hydrogen atom, electron has an angular momentum equal to:
- A$\frac{\pi}{\text{h}}$
- B$\frac{\text{h}}{\pi}$
- C$\frac{\text{h}}{2\pi}$
- D$\frac{2\pi}{\text{h}}$
Explanation:
The angular momentumL = mevr is on integer multiple of $\frac{\text{h}}{2\pi}$
$\text{mvr}=\frac{\text{nh}}{2\pi}$
For, n = 1
$\text{mvr}=\frac{\text{h}}{2\pi}$
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| Column $I$ | Column $II$ |
| $(a)\,XeO_6^{-4}$ | $(P)$ Tetrahedral |
| $(b)\,ClO_2$ | $(Q)\,V-$ Shape |
| $(c)\,NH_4^+$ | $(R)$ Trigonal Bipyramidal |
| $(d)\,XeO_3F_2$ | $(S)$ Octahedral |