MCQ
In the modern periodic table, elements are arranged in
  • A
    Increasing mass
  • B
    Increasing volume
  • Increasing atomic number
  • D
    Alphabetically

Answer

Correct option: C.
Increasing atomic number
c
(c) Increasing atomic number. Mosley found that atomic no. was better fundamental property than atomic weight.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A $400\, mg$ iron capsule contains $100\, mg$ of ferrous fumarate, ${(CHCOO)_2}Fe$. The percentage of iron pasent in it is approximately ........... $\%$
Chloroform can be obtained from
The maximum number of electrons in $p$-orbital with $n = 5,\,m = 1$ is
White precipitate of $AgCl$ dissolves in aqueous ammonia solution due to formation of ..... .
Stadard electromotive force for following cell is $ Zn|Zn^{+2}\, (1\,M)| |I^{\circleddash}\,(1\,M)| CuI| Cu$ if halfcell reaction ........... $\mathrm{V}$

$CuI_{(s)} + e^{\circleddash} \to Cu_{(s)} + I^{\circleddash}_{(aq)}$ ;  $E^o = -0.17\, V$

$Zn^{+2}_{(aq)} + 2e^{\circleddash} \to  Zn_{(s)}$  ;   $E^o = -0.76\, V$

For the electrophilic substitution reaction involving nitration, which of the following sequence regarding the rate of reaction is true ?
"A" obtained by Ostwald's method involving air oxidation of $NH _3$, upon further air oxidation produces "B". "B" on hydration forms an oxoacid of Nitrogen along with evolution of "A". The oxoacid also produces "A" and gives positive brown ring test
Incorrect set is

 $(a)$ Ionisation energy $(Na < Li < B < Be)$

$(b)$ Electron affinity $(N < P < O < S)$

$(c)$ Electron negativity $(S < O < Cl < F)$

$(d)$ Atomic radii $(F < N < O < Na)$

Following figure shows a graph in $log_{10}K$ vs $\frac{1}{T}$ where $K$ is rate constant and $T$ is temperature. The straight line $BC$ has slope, $tan\,\theta  = -\frac{1}{2.303}$ and an intercept of $5$ on $Y-$ axis. Thus $E_a$, the energy of activation is ....... $cal$
Assertion : $PbCl_2$ is more stable than $PbCl_4$.

Reason : $PbCl_4$ is powerful oxidising agent.