MCQ
In the periodic table going down in fluorine group
  • A
    Reactivity will increase
  • B
    Electronegativity will increase
  • Ionic radius will increase
  • D
    Ionization potential will increase

Answer

Correct option: C.
Ionic radius will increase
c
(c) Ionic radius will increase as number of shells increases

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The oxidation number of $Cr$ in $K_3CrO_8$ is $+5$ how many peroxy linkages are present in this molecule
Class $XII$ students were asked to prepare one litre of buffer solution of $pH\,8.26$ by their chemistry teacher. The amount of ammonium chloride to be dissolved by the student in $0.2\,M$ ammonia solution to make one litre of the buffer is $.....\,g$ (Given $pK _{ b }\left( NH _{3}\right)=4.74$; Molar mass of $NH _{3}=17\,g\,mol ^{-}$ ; Molar mass of $NH _{4} Cl =53.5\,g\,mol ^{-1}$ )
The $IUPAC$ name of $\begin{matrix}
   C{{H}_{3}}-CH-C-C-NH  \\
   \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,|  \\
   \,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,O\,\,\,\,\,\,\,O\,\,\,\,\,\,Br  \\
\end{matrix}$ is
The dissociation constant of a substituted benzoic acid at $25^{\circ} \mathrm{C}$ is $1.0 \times 10^{-4}$. The $\mathrm{pH}$ of a $0.01 \ \mathrm{M}$ solution of its sodium salt is
What is $X$ in the following reaction?
What is the formal charge on the nitrogen atom in $HNO _3$ ?
Image
Number of compounds which give reaction with Hinsberg's reagent is____.
A lanthanoid has $'n'$ unpaired electrons and another lanthanoid has $(14-n)$ unpaired electrons. It means
The catalyst used in the contact process is
The heat of solution of anhydrous $\mathrm{CuSO}_4$ and $\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}$ are $-70 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and $+12 \mathrm{~kJ} \mathrm{~mol}^{-1}$ respectively.

The heat of hydration of $\mathrm{CuSO}_4$ to $\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}$ is $-\mathrm{xkJ}$. The value of $\mathrm{x}$ is. . . . . . .