- ANumber of molecules
- BAtomic number
- CMass number
- ✓Number of moles
Writing the units of all the terms of Right Hand Side, in $SI$ units
$n=\frac{(P a) \times\left(m^{3}\right)}{(J / mol / k) \cdot(k)}$
$n=\frac{\left(\frac{N}{m^{2}}\right) \cdot\left(m^{3}\right)}{\left(\frac{J}{\text { mol. K }}\right) \cdot(k .)}$
$n=\frac{\frac{ kgm }{ s ^{2} \cdot m ^{2}} \cdot m ^{3}}{\frac{ kg m ^{2}}{ s ^{2} \cdot mol \cdot K } \cdot K .}$
$n=\operatorname{mol}$. [All other terms cancel out]
Correct choice - option - $D$
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(considering $4\ kg$ block doesn't fall on ground)
Consider the following statements
$(i)$ Time when relative motion between them is stopped is $1.4\ second$.
$(ii)$ Time when relative motion between them is stopped in $1.2\ second$
$(iii)$ The common velocity of the two blocks is $8\ m/s$, towards right.
$(iv)$ The displacement of the $4\, kg$ block when relative motion stopped is$10.8\ m$.
Which of the fstatements is/are correct
$\left[\rho_{\text {(liquid) }}=900\; kg\,m ^{-3}, g =10\, ms ^{-2}\right]$ (Give answer in closest integer)