In the situation as shown in figure time period of vertical oscillation of block for small displacements will be
Advanced
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A simple harmonic oscillator of angular frequency $2\,rad\,s^{-1}$ is acted upon by an external force $F = sin\,t\,N .$ If the oscillator is at rest in its equilibrium position at $t = 0,$ its position at later times is proportional toView Solution
- 2Consider two identical springs each of spring constant $k$ and negligible mass compared to the mass $M$ as shown. Fig. $1$ shows one of them and Fig. $2$ shows their series combination. The ratios of time period of oscillation of the two $SHM$ is $\frac{ T _{ b }}{ T _{ a }}=\sqrt{ x },$ where value of $x$ isView Solution
(Round off to the Nearest Integer)
- 3Two particles are executing simple harmonic motion of the same amplitude $A$ and frequency $\omega$ along the $x-$axis. Their mean position is separated by distance $X_0(X_0 > A).$ If the maximum separation between them is $(X_0 + A)$, the phase difference between their motion is:View Solution
- 4Length of a simple pendulum is $l$ and its maximum angular displacement is $\theta$, then its maximum $K.E.$ isView Solution
- 5The angular velocity and the amplitude of a simple pendulum is $'\omega '$ and $'A'$ respectively. At a displacement $x$ from the mean position its kinetic energy is $'T'$ and potnetial energy is $'V'$. Then the ratio $\frac{V}{T}$ isView Solution
- 6Two simple harmonic motions are represented by the equations $x_{1}=5 \sin \left(2 \pi t+\frac{\pi}{4}\right), x_{2}=5 \sqrt{2}(\sin 2 \pi t+\cos 2 \pi t)$ The ratio of the amplitude of $x_{1}$ and $x_{2}$ isView Solution
- 7Assume that a tunnel is dug along a chord of the earth, at a perpendicular distance $( R / 2)$ from the earth's centre, where $'R'$ is the radius of the Earth. The wall of the tunnel is frictionless. If a particle is released in this tunnel, it will execute a simple harmonic motion with a time periodView Solution
- 8The displacement $x$ (in metres) of a particle performing simple harmonic motion is related to time $t$ (in seconds) as $x = 0.05\cos \left( {4\,\pi \,t + \frac{\pi }{4}} \right)$. The frequency of the motion will be ..... $Hz$View Solution
- 9A $1.00 \times 10^{-20} \,kg$ particle is vibrating under simple harmonic motion with a period of $1.00 \times 10^{-5} \,s$ and with a maximum speed of $1.00 \times 10^3 \,m / s$. The maximum displacement of particle from mean position is .......... $mm$View Solution
- 10A mass $0.9\,kg$, attached to a horizontal spring, executes $SHM$ with an amplitude $A _{1}$. When this mass passes through its mean position, then a smaller mass of $124\,g$ is placed over it and both masses move together with amplitude $A _{2}$. If the ratio $\frac{ A _{1}}{ A _{2}}$ is $\frac{\alpha}{\alpha-1}$, then the value of $\alpha$ will be$......$View Solution