Question
In $\triangle\text{ABC},$ it is given that base $= 12\ cm$ and height $= 5\ cm. $ Its area is:
$30\ cm^2$
Area of triangle $=\frac{1}{2}\times\text{Base}\times\text{Height}$
Are of $\triangle\text{ABC}=\frac{1}{2}\times12\times5$
$= 30\ cm^2$
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