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Statistics — MATHS STD 9 — Question

Rajasthan BoardEnglish MediumSTD 9MATHSStatistics1 Mark
Question
Write the correct answer in the following:
Let m be the mid-point and l be the upper class limit of a class in a continuous frequency distribution. The lower class limit of the class is:
✓

Answer

  1. 2m - l
Solution:
Let x and y be the lower and upper class limit of a continuous frequency distribution.
Now, mid-point of a class $=\frac{(\text{x}+\text{y})}{2}=\text{m}$ [given]
⇒ x + y = 2m = x + l = 2m
$\big[\therefore$ y = l = upper class limit (given)$\big]$
⇒ x = 2m - l
Hence, the lower class limit of the class is 2m - l.

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