In Wheatstone's bridge P = 9, ohm, Q = 11, ohm, R = 4,ohm and S = 6,ohm. How much resistance must be put in

Q: In Wheatstone's bridge $P = 9\, ohm$, $Q = 11\, ohm$, $R = 4\,ohm$ and $S = 6\,ohm$. How much resistance must be put in parallel to the resistance $S$ to balance the bridge ............... $ohm$

c $\frac{P}{Q} = \frac{R}{{S'}}$ (For balancing bridge) $ \Rightarrow $ $S' = \frac{{4 \times 11}}{9} = \frac{{44}}{9}$ $ \Rightarrow $ $\frac{1}{{S'}} = \frac{1}{r} + \frac{1}{6}$ $ \Rightarrow $ $\frac{9}{{44}} - \frac{1}{6} = \frac{1}{r}$ $ \Rightarrow $ $r = \frac{{132}}{5} = 26.4\,\Omega $

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

In Wheatstone's bridge $P = 9\, ohm$, $Q = 11\, ohm$, $R = 4\,ohm$ and $S = 6\,ohm$. How much resistance must be put in parallel to the resistance $S$ to balance the bridge ............... $ohm$

A$24$
B$\frac{{44}}{9}$
C$26.4$
D$18.7$

Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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