MCQ
Incorrect order of ionic radius is
- A$Na^+ > Mg^{+2} > Al^{+3}$
- B$V^{+2} > V^{+3} > V^{+4} > V^{+5}$
- C$K^+ > Sc^{+3} > V^{+5} > Mn^{+7}$
- ✓$O^{-2} > Rb^+ > Sr^{+2} > Cs^+$
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Product $(A)$ of the reaction is


then the solubility of $AB _{2}$ in pure water is......... $\times 10^{-4}$ $mol$ $L ^{-1}$.
[Assuming that neither kind of ion reacts with water]
