MCQ
$\int \limits_{-\pi}^{\pi}|\pi-| x || d x$ is equal to :
  • $\pi^{2}$
  • B
    $2 \pi^{2}$
  • C
    $\sqrt{2} \pi^{2}$
  • D
    $\frac{\pi^{2}}{2}$

Answer

Correct option: A.
$\pi^{2}$
a
$\int_{-\pi}^{\pi}|\pi-| x || d x =2 \int_{0}^{\pi}|\pi- x | d x$

$=2 \int_{0}^{\pi}(\pi- x ) d x$

$=2\left[\pi x -\frac{ x ^{2}}{2}\right]_{0}^{\pi}=\pi^{2}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The area bounded by the curve $y=x^2-1$ and the straight line $x + y = 3$ is:
By graphical method, the solution of linear programming problem
Maximize $Z = 3x_1 + 5x_2$
Subject to
$3x_1 + 2x_2 \leq 18$
$x_1 \leq 4$
$x_2 \leq 6$
$x1 \geq 0, x2 \geq 0$, is:
If $u = {\tan ^{ - 1}}{y \over x}$, then by Euler’s Theorem the value of $x$ ${{\partial u} \over {\partial x}} + y{{\partial u} \over {\partial y}} = $
The slope of the tangent to a curve $y = f (x)$ at $(x , f (x))$ is $2x + 1 .$ If the curve passes through the point $(1 , 2)$ then the area of the region bounded by the curve , the $x-$ axis and the line $x = 1$ is :
Let $h (x) = f (x) - \{f (x)\}^2+ \{f  (x)\}^3$ for every real number '$ x $' , then
Let $y=y(x)$ be the solution of the differential equation

$\frac{d y}{d x}=1+x e^{y-x},-\sqrt{2}\,<\,x\,<\,\sqrt{2}, y (0)=0$ then, the minimum value of $y(x)$ , $\mathrm{x} \in(-\sqrt{2}, \sqrt{2})$ is equal to:

If $\int \operatorname{cosec}^5 x d x=\alpha \cot x \operatorname{cosec} x\left(\operatorname{cosec}^2 x+\frac{3}{2}\right)+\beta \log _e\left|\tan \frac{x}{2}\right|+C$ where $\alpha, \beta \in \mathbb{R}$ and $\mathrm{C}$ is constant of integration , then the value of $8(\alpha+\beta)$ equals....................
If the function $\text{f}(\text{x})=\cos|\text{x}|-2\text{ax}+\text{b}$ increases along entire number scale, then :
The value of $c$ in Rolle's theorem for the function $\text{f}(\text{x})=\frac{\text{x}(\text{x}+1)}{\text{e}^{\text{x}}}$ defined on $[-1, 0]$ is:
Solution of differential equation $\frac{{dy}}{{dx}} = \frac{1}{{xy({x^2}\sin {y^2} + 1)}}$ (where $C$ is integral constant)