MCQ
$\int_{\,0}^{\,1000} {{e^{x - [x]}}dx} $ is
  • A
    ${e^{1000}} - 1$
  • B
    $\frac{{{e^{1000}} - 1}}{{e - 1}}$
  • $1000(e - 1)$
  • D
    $\frac{{e - 1}}{{1000}}$

Answer

Correct option: C.
$1000(e - 1)$
c
(c) ${e^{x - [x]}}$ is a periodic function with period $1$.

$\therefore \int_0^{1000} {{e^{x - [x]}}dx = 1000\int_0^1 {{e^{x - [x]}}dx} } $,

$[\because [x]=0,$ if $\,0 < x < 1]$

$ = 1000{\rm{ }}\,[{e^x}]_0^1$

$ = 1000\,(e - 1)$.

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