Explanation:
In a mixture of benzene and toluene intermolecular forces between benzene and toluene molecules would be nearly of the same strength as those of two benzene molecules and two toluene molecules separately. The solution will, therefore, form an ideal solution & obey Raoult’s law. So, the option (iii) & (iv) is not true.
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$\text{H}^+(\text{aq})+\text{e}^-\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ \ \ }\frac{1}{2}\text{H}_2(\text{g});\ \ \ \ \ \text{E}^\ominus_{\text{Cell}}=0.00\text{V}$
$2\text{H}_2\text{O}_{(\text{l})}\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ \ \ \ }\text{O}_{2(\text{g})}+4\text{H}^{+}_{(\text{aq})}+4\text{e}^-;\ \ \ \ \ \text{E}^0_{\text{Cell}}=1.23\text{V}$
$2\text{SO}^{2-}_{4(\text{aq})}\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ \ \ }\text{S}_2\text{O}^{2-}_{8(\text{aq})}+2\text{e}^-;\ \ \ \ \ \text{E}^0_{\text{cell}}=1.96\text{V}$