MCQ
$\int\limits_{\pi /4}^{3\pi /4} {\frac{{dx}}{{1 + \cos x}}} $ is equal to
- ✓$2$
- B$ - 2$
- C$\frac{1}{2}$
- D$ - \frac{1}{2}$
$\int_{\pi /4}^{3\pi /4} {\frac{{1 - \cos x}}{{1 - {{\cos }^2}x}}} \,dx = \int_{\pi /4}^{3\pi /4} {\frac{{1 - \cos x}}{{{{\sin }^2}x}}} \,dx$
$ = \int_{\pi /4}^{3\pi /4} {({\rm{cose}}{{\rm{c}}^2}x} - \cot x{\rm{cosec}}\,x)\,dx$
$ = \,( - \cot x + {\rm{cosec}}\,x{\rm{)}}_{\pi {\rm{/4}}}^{{\rm{3}}\pi {\rm{/4}}} = 2$.
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