MCQ
Iodine is formed when $ KI $ reacts with a solution of
- ✓$CuS{O_4}$
- B${(N{H_4})_2}S{O_4}$
- C$ZnS{O_4}$
- D$FeS{O_4}$
✓
Answer
Correct option: A.
$CuS{O_4}$
(a)Iodine being a strong reducing agent reduce $C{u^{2 + }}$ ions to $C{u^ + }$ ions and itself gets oxidised to iodine.
$\mathop {2CuS{O_4}}\limits_{{\rm{Reduced}}}^{ + 2} + \mathop {4KI}\limits_{{\rm{Oxidised}}}^{ - 1} \to \mathop {C{u_2}{I_2}}\limits^{ + 1} + \mathop {{I_2}}\limits^0 + 2{K_2}S{O_4}$
$\mathop {2CuS{O_4}}\limits_{{\rm{Reduced}}}^{ + 2} + \mathop {4KI}\limits_{{\rm{Oxidised}}}^{ - 1} \to \mathop {C{u_2}{I_2}}\limits^{ + 1} + \mathop {{I_2}}\limits^0 + 2{K_2}S{O_4}$
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