{\frac{{\sqrt 3 }}{2}}&{\frac{1}{2}}\\
{ - \frac{1}{2}}&{\frac{{\sqrt 3 }}{2}}
\end{array}} \right],\,A = \,\left[ {\begin{array}{*{20}{c}}
1&1\\
0&1
\end{array}} \right]$ અને $Q=PAP^T,$ તો $P^T$ $Q^{2015}$ $P$ = . . . .
- A$\,\left[ {\begin{array}{*{20}{c}} 0&{2015}\\ 0&0 \end{array}} \right]$
- B$\,\left[ {\begin{array}{*{20}{c}} {2015}&0\\ 1&{2015} \end{array}} \right]$
- ✓$\left[ {\begin{array}{*{20}{c}} 1&{2015}\\ 0&1 \end{array}} \right]$
- D$\left[ {\begin{array}{*{20}{c}} {2015}&1\\ 0&{2015} \end{array}} \right]$