MCQ
Last element of group-$IV$ is found to be
- AStrong metallic
- ✓Weak metallic
- CStrong non-metallic
- DWeak non-metallic
✓
Answer
Correct option: B.
Weak metallic
b
Down the group metallic character increases. Group $IV$ shows variation from non-metallic character to weak metallic character as we move down the group.
Down the group metallic character increases. Group $IV$ shows variation from non-metallic character to weak metallic character as we move down the group.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Liquid $'M\ ’$ and liquid $'N\ ’$ form an ideal solution. The vapour pressures of pure liquids $'M\ ’$ and $'N\ ’$ are $450$ and $700\,\ce{mm\ Hg,}$ respectively at the same temperature. Then correct statement is$: ( x_M =$ mole fraction of $'M\ ’$ in solution $;x_N =$ mole fraction of $'N\ ’$ in solution$; y_M =$ mole fraction of $'M\ ’$ in vapour phase; $y_N =$ mole fraction of $'M\ ’$ in vapour phase$)$
→Which of the following $3d$ bivalent metal ions has the smallest number of unpaired $d$ electrons
→$N{H_4}Cl$ is acidic, because
→Three molecules of acetone in the presence of dry $HCl$ form
→$HN{O_3}$ in aqueous solution yields
→An ideal gas undergoes a cyclic process as shown in Figure
→$\Delta {U_{BC}} = - 5\,kJ\,mo{l^{ - 1}},{q_{AB}} = 2\,kJ\,mo{l^{ - 1}}$
$\Delta {W_{AB}} = - 5\,kJ\,mo{l^{ - 1}},{W_{CA}} = 3\,kJ\,mo{l^{ - 1}}$
Heat absorbed by the system during process $CA$ is......$kJ\,mo{l^{ - 1}}$
Assertion : Resorcinol turns $FeCl_3$ solution purple.
Reason : Resorcinol have phenolic group
→Reason : Resorcinol have phenolic group
The number of sigma ( $\sigma$ ) and pi ( $\pi$ ) bonds in pent$- 2 -$en$- 4 -$yne is
→In which reaction last product is $Ph -C \equiv CH$ ?
→The Molarity (M) of an aqueous solution containing 5.85 g of NaCl in 500 mL water is:
(Given: Molar Mass Na : 23 and Cl : 35.5 $gmol ^{-1}$
→(Given: Molar Mass Na : 23 and Cl : 35.5 $gmol ^{-1}$