- A${H_2}(g)\, + \,{I_2}(g)\,\, \rightleftharpoons \,\,2HI(g)$
- ✓$Fe(s)\,\, + \,S(s)\, \rightleftharpoons \,FeS(s)$
- C${N_2}(g)\, + \,3{H_2}(g)\,\, \rightleftharpoons \,\,2NH_3(g)$
- D${N_2}(g)\, + \,{O_2}(g)\,\, \rightleftharpoons \,\,2NO(g)$
Le- Chatelier principle is applicable only to gases. But it is not necessary that in a certain chemical reaction, all the reactants species must be in gaseous phase. $Fe ( s )+ S ( s ) \rightleftharpoons FeS ( s )$ is in solid equilibrium phase.
Hence, Le- Chatelier principle is not applicable.
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$(A)$ $n=4,1=1$ $(B)$ $\mathrm{n}=4,1=2$ $(C)$ $\mathrm{n}=3,1=1$ $(D)$ $\mathrm{n}=3,1=2$ $(E)$ $n=4,1=0$
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$(1)$ $\frac{3}{2} O _2( g ) \rightarrow O _3$ $(g)$
$(2)$ $\frac{1}{8} S _8( s )+ O _2( g ) \rightarrow SO _2( g )$
$(3)$ $2 H _2( g )+ O _2( g ) \rightarrow 2 H _2 O (l)$
$(4)$ $2 C ( g )+3 H _2( g ) \rightarrow C _2 H _6( g )$

| List $I$ (molecules/ions) | List $II$ (No. of lone pairs of $e ^{-}$ on central atom) |
| $A$ $IF_7$ | $I$ Three |
| $B$ $ICl^{-}_4$ | $II$ One |
| $C$ $XeF_6$ | $III$ Two |
| $D$ $XeF_2$ | $IV$ Zero |
Choose the correct answer from the options given below: