MCQ
${\left[ {\begin{array}{*{20}{c}}1&3\\3&{10}\end{array}} \right]^{ - 1}} = $
  • A
    $\left[ {\begin{array}{*{20}{c}}{10}&3\\3&1\end{array}} \right]$
  • $\left[ {\begin{array}{*{20}{c}}{10}&{ - 3}\\{ - 3}&1\end{array}} \right]$
  • C
    $\left[ {\begin{array}{*{20}{c}}1&3\\3&{10}\end{array}} \right]$
  • D
    $\left[ {\begin{array}{*{20}{c}}{ - 1}&{ - 3}\\{ - 3}&{ - 10}\end{array}} \right]$

Answer

Correct option: B.
$\left[ {\begin{array}{*{20}{c}}{10}&{ - 3}\\{ - 3}&1\end{array}} \right]$
b
(b) As $\left[ {\begin{array}{*{20}{c}}1&3\\3&{10}\end{array}} \right]\,\,\left[ {\begin{array}{*{20}{c}}{10}&{ - 3}\\{ - 3}&1\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}1&0\\0&1\end{array}} \right]$.

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