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STD 12 - 2. inverse trigonometric function — Mathematics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceMathematicsSTD 12 - 2. inverse trigonometric function1 Mark
MCQ
${\left[ {\sin \left( {{{\tan }^{ - 1}}\frac{3}{4}} \right)} \right]^2} = $
  • A
    $\frac{3}{5}$
  • B
    $\frac{5}{3}$
  • ✓
    $\frac{9}{{25}}$
  • D
    $\frac{{25}}{9}$
✓

Answer

Correct option: C.
$\frac{9}{{25}}$
c
(c)${\left[ {\sin \,\left( {{{\tan }^{ - 1}}\frac{3}{4}} \right)} \right]^2} = {\left[ {\sin \,\left( {{{\sin }^{ - 1}}\frac{3}{5}} \right)} \right]^2} = {\left( {\frac{3}{5}} \right)^2} = \frac{9}{{25}}$.

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