, | , * 20 c 1&1&1 1&2&3 1&3&6 , | . . . . - Vidyadip

MCQ

$\,\left| {\,\begin{array}{*{20}{c}}1&1&1\\1&2&3\\1&3&6\end{array}\,} \right| \ne . . . .$

✓
$\left| {\,\begin{array}{*{20}{c}}2&1&1\\2&2&3\\2&3&6\end{array}\,} \right|$
B
$\left| {\,\begin{array}{*{20}{c}}2&1&1\\3&2&3\\4&3&6\end{array}\,} \right|$
C
$\left| {\begin{array}{*{20}{c}}1&2&1\\1&5&3\\1&9&6\end{array}} \right|$
D
$\left| {\,\begin{array}{*{20}{c}}3&1&1\\6&2&3\\{10}&3&6\end{array}} \right|\,$

✓

Answer

Correct option: A.

$\left| {\,\begin{array}{*{20}{c}}2&1&1\\2&2&3\\2&3&6\end{array}\,} \right|$

(a) $\left| {\,\begin{array}{*{20}{c}}1&1&1\\1&2&3\\1&3&6\end{array}\,} \right|\, = \,\left| {\,\begin{array}{*{20}{c}}2&1&1\\3&2&3\\4&3&6\end{array}\,} \right|$ by ${C_1} \to {C_1} + {C_2}$

= $\left| {\,\begin{array}{*{20}{c}}
1&2&1\\
1&5&3\\
1&9&6
\end{array}\,} \right|\,$ by ${C_2} \to {C_2} + {C_3}$

= $\left| {\,\begin{array}{*{20}{c}}3&1&1\\6&2&3\\{10}&3&6\end{array}\,} \right|$, by ${C_1} \to {C_1} + {C_2} + {C_3}$.

But $ \ne \left| {\,\begin{array}{*{20}{c}}2&1&1\\2&2&3\\2&3&6\end{array}\,} \right|$.

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