MCQ
સમીકરણ ${\sin ^{ - 1}}x = 2{\tan ^{ - 1}}x$ નો ઉકેલગણ મેળવો.
- A$\{1, 2\}$
- B$\{-1, 2\}$
- ✓$\{-1,1, 0\}$
- D$\{1, \frac{1}{2} , 0\}$
==> ${\sin ^{ - 1}}x = {\sin ^{ - 1}}\frac{{2x}}{{1 + {x^2}}}$
$ \Rightarrow \frac{{2x}}{{1 + {x^2}}} = x$ ==> ${x^3} - x = 0$
==> $x(x + 1)(x - 1) = 0$ ==> $x = \left\{ { - 1,\,\,1,\,\,0} \right\}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| $X$ | $0$ | $2$ | $4$ | $6$ | $8$ |
| $P(X)$ | $a$ | $2a$ | $a+b$ | $2b$ | $3b$ |
નું મધ્યક જો $\frac{46}{9}$ હોય, તો વિતરણ નું વિચરણ ............ છે.