Length of a hollow tube is 5,m, it’s outer diameter is 10, cm and thickness of it’s wall is 5, mm. If resistivity of the

Q: Length of a hollow tube is $5\,m$, it’s outer diameter is $10\, cm$ and thickness of it’s wall is $5\, mm$. If resistivity of the material of the tube is $1.7 \times 10^{-8} \,\Omega m$ then resistance of tube will be

a (a) By using $R = \rho .\frac{l}{A};$ here $A = \pi (r_2^2 - r_1^2)$ Outer radius $r_2 = 5\,cm$ Inner radius $r_1 = 5 -0.5 = 4.5\, cm$ So $R = 1.7 \times {10^{ - 8}} \times \frac{5}{{\pi \{ {{(5 \times {{10}^{ - 2}})}^2} - {{(4.5 \times {{10}^{ - 2}})}^2}\} }}$ $ = 5.6 \times {10^{ - 5}}\,\Omega $

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Length of a hollow tube is $5\,m$, it’s outer diameter is $10\, cm$ and thickness of it’s wall is $5\, mm$. If resistivity of the material of the tube is $1.7 \times 10^{-8} \,\Omega m$ then resistance of tube will be

A$5.6 \times 10^{-5} \,\Omega$
B$2 \times 10^{-5}\,\Omega$
C$4 \times 10^{-5} \,\Omega$
D
None of these

Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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