Question
Let l be the lower class limit of a class-interval in a frequency distribution and m be the mid point of the class. Then, the upper class limit of the class is:

Answer

  1. $2\text{m}-1$
Solution:
Given that, the lower class limit of a class-interval is l and the mid-point of the class is m. Let u be the upper class limit of the class-interval.
Therefore, we have
$\text{m}=\frac{\text{l+u}}{2}$
⇒ l + u = 2m
⇒ u = 2m - l
Thus the upper class limit of the class is (2m - l).
Hence, the correct choice is (c).

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