- A$\sqrt{7}$
- ✓$\sqrt{2}$
- C$2$
- D$7$
$\overrightarrow{ a }=\lambda\left(\frac{1}{\sqrt{3}} \hat{ i }+\frac{1}{\sqrt{3}} \hat{ j }+\frac{1}{\sqrt{3}} \hat{ k }\right)=\frac{\lambda}{\sqrt{3}}(\hat{ i }+\hat{ j }+\hat{ k }$
Now projection of $\vec{a}$ on $\vec{b}=7$
$\Rightarrow \frac{\overrightarrow{ a } \cdot \overrightarrow{ b }}{|\overrightarrow{ b }|}=7$
$\frac{\lambda}{\sqrt{3}} \frac{(\hat{ i }+\hat{ j }+\hat{ k }) \cdot(3 \hat{ i }+4 \hat{ j })}{5}=7$
$\lambda=5 \sqrt{3}$
$\overrightarrow{ a }=5(\hat{ i }+\hat{ j }+\hat{ k })$
now $\overrightarrow{ b }=5 \alpha(\hat{ i }+\hat{ j }+\hat{ k })+\beta(\hat{ i })$
$\overrightarrow{ a } \cdot \overrightarrow{ b }=0$
$\Rightarrow 25 \alpha(3)+5 \beta=0$
$\Rightarrow 15 \alpha+\beta=0 \Rightarrow \beta=-15 \alpha$
$\overrightarrow{ b }=5 \alpha(-2 \hat{ i }+\hat{ j }+\hat{ k })$
$|\vec{b}|=5 \sqrt{3}$
$\Rightarrow \alpha=\pm \frac{1}{\sqrt{2}}$
$\vec{b}=\pm \frac{5}{\sqrt{2}}(-2 \hat{i}+\hat{j}+\hat{k})$
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